10 Bags Puzzle Find the bag with defective coins
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Date: 2023-11-15
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Comments and reviews: 21
Shubham
The thing you are doing wrong to give the solution is that you are taking only 3 bags. instead we will take all 10 bags and put 1 coin from bag 1 and 2 coins from bag 2 and 3 coins from bag 3 and so on up to 10 coins from bag 10.
Since all the defected coins are in the same bag. The weigh less than total 550 will show us the bag number. Like if there 6 gm less then all coins should be from same bag and 6 coins are from bag no. 6
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The thing you are doing wrong to give the solution is that you are taking only 3 bags. instead we will take all 10 bags and put 1 coin from bag 1 and 2 coins from bag 2 and 3 coins from bag 3 and so on up to 10 coins from bag 10.
Since all the defected coins are in the same bag. The weigh less than total 550 will show us the bag number. Like if there 6 gm less then all coins should be from same bag and 6 coins are from bag no. 6
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Anjana
Take one coin from each bag, weigh all the coin together and keep the coins so that you can identify which coin is from which bag. Now remove the coins one by one. Whenever you remove a coin check if the weight is decreased by 10 or 9 gm, if it decreased by 9 gm it is defective and the bag cointaining it is also defective.
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Take one coin from each bag, weigh all the coin together and keep the coins so that you can identify which coin is from which bag. Now remove the coins one by one. Whenever you remove a coin check if the weight is decreased by 10 or 9 gm, if it decreased by 9 gm it is defective and the bag cointaining it is also defective.
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alex
Bro I can identify defective bag without weighing Machine how?
I will take 10 coins from 10 bags and then take 2 coins from them and throw them from same height. 10gm will reach ground first. and eventually I will come to know which coin is defective. explanation is based on Galileo s principle.
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Bro I can identify defective bag without weighing Machine how?
I will take 10 coins from 10 bags and then take 2 coins from them and throw them from same height. 10gm will reach ground first. and eventually I will come to know which coin is defective. explanation is based on Galileo s principle.
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Devon
putting all 10 bags on the machine, then removing one bag at a time and whenever you have a zero as a unit digit while removing, then the bag in your hand is defective. so if after removing the first bag, 90lb is on the scale, then the first bag is defective and weight 9lb.
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putting all 10 bags on the machine, then removing one bag at a time and whenever you have a zero as a unit digit while removing, then the bag in your hand is defective. so if after removing the first bag, 90lb is on the scale, then the first bag is defective and weight 9lb.
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hunar
Amar I have a more reliable approach, take one coin from each bag and put on machine. As all coin are 10 gram but one is 9 gram it show 99 gram now remove coin one by one. It always decrease by 10 gram if coin is perfect but in defective case it decrease by 9 gram.
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Amar I have a more reliable approach, take one coin from each bag and put on machine. As all coin are 10 gram but one is 9 gram it show 99 gram now remove coin one by one. It always decrease by 10 gram if coin is perfect but in defective case it decrease by 9 gram.
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Koushik
From the first bag I wont take any coin, from the second bag onwards I will take like u have taken. 1 coin from the second bag, 2 coins from the third bag, 3 coins from the fourth bag and so on. so I have to take 10 coin less than urs.
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From the first bag I wont take any coin, from the second bag onwards I will take like u have taken. 1 coin from the second bag, 2 coins from the third bag, 3 coins from the fourth bag and so on. so I have to take 10 coin less than urs.
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Cas
Yeah that's good n'all, but you know what would be easier? Putting all the bags on at once and removing them one by one to see which removal changes the scale by a different amount. Thinking inside common sense, not outside the box: )
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Yeah that's good n'all, but you know what would be easier? Putting all the bags on at once and removing them one by one to see which removal changes the scale by a different amount. Thinking inside common sense, not outside the box: )
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SgtSupaman
Good riddle with interesting solution. I was just going to weigh one bag to see if it was the good or bad coins, then compare the rest of them by hand (if every coin in the bag is lighter, the bag should be noticeably lighter.
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Good riddle with interesting solution. I was just going to weigh one bag to see if it was the good or bad coins, then compare the rest of them by hand (if every coin in the bag is lighter, the bag should be noticeably lighter.
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Ayushee
I have another solution. (Not sure if this is accurate enough.
Take out 1 coin from each bag and place it on the machine, one by one. The moment the reading shows less wt. , we can find out the bag with defective coins.
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I have another solution. (Not sure if this is accurate enough.
Take out 1 coin from each bag and place it on the machine, one by one. The moment the reading shows less wt. , we can find out the bag with defective coins.
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Douglas
I don't your -optimal- solution is better. The solution with weighing 55 coins would also spot the case where you have been lied to and there are no bags with defective coins, thus I would argue that solution is better.
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I don't your -optimal- solution is better. The solution with weighing 55 coins would also spot the case where you have been lied to and there are no bags with defective coins, thus I would argue that solution is better.
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Gharud_xD
I have one another solution so took one coin form each bag and put your hand by same number and put it in row formation then remove one by one finnally you will get answer -
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I have one another solution so took one coin form each bag and put your hand by same number and put it in row formation then remove one by one finnally you will get answer -
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moonyuen0505
There is an additional question:
there are 10 bags of coins but you dont know how many bags are fake coins.
same situation, how can you solve that?
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There is an additional question:
there are 10 bags of coins but you dont know how many bags are fake coins.
same situation, how can you solve that?
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Aakriti
thank you very much for making this video. i have been trying to look for answer and its there on other sites too but only visually it has become more clear.
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thank you very much for making this video. i have been trying to look for answer and its there on other sites too but only visually it has become more clear.
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Lol
It becomes so much easier when you got a system to figure it out. but the hard part IS to figure out a system
Sorry about my English not my first language
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It becomes so much easier when you got a system to figure it out. but the hard part IS to figure out a system
Sorry about my English not my first language
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Marvin
0: 15 but you state that the defective bag has FOUR defective coins.
You do not state how many coins are in the bags.
This makes it unsolvable.
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0: 15 but you state that the defective bag has FOUR defective coins.
You do not state how many coins are in the bags.
This makes it unsolvable.
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blargg
And for good measure, double the quantities of each coin because the tolerances of the coins and scale's accuracy might make it one gram off.
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And for good measure, double the quantities of each coin because the tolerances of the coins and scale's accuracy might make it one gram off.
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Ghazi
What if we just place one coin from each bag and remove it one bye one
When the weight shows 0 at last that will be defective coin.
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What if we just place one coin from each bag and remove it one bye one
When the weight shows 0 at last that will be defective coin.
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w0ttheh3ll
take n coins from the n-th bag (starting with n=1) and pile them up until you run out of bags. put the pile on the scale.
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take n coins from the n-th bag (starting with n=1) and pile them up until you run out of bags. put the pile on the scale.
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Epic
Just Keep All The Bags on the machine And Take The Bags One By One out You will Get the defective one ( Why So Complicated )
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Just Keep All The Bags on the machine And Take The Bags One By One out You will Get the defective one ( Why So Complicated )
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Rajesh
From first bag take one coin, second bag 2coinns, tenth bag 10 coins
Now based on d wait we can find in which bag
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From first bag take one coin, second bag 2coinns, tenth bag 10 coins
Now based on d wait we can find in which bag
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RandomPikachu
you did not mentioned the total no. of coins in each bag. what if each bag have less than 10 coins in it.
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you did not mentioned the total no. of coins in each bag. what if each bag have less than 10 coins in it.
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