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zakruti.com » Knowledge, science, education » Numberphile
How many ways can circles overlap? - Numberphile

How many ways can circles overlap? - Numberphile

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How many ways can circles overlap? nick012000: -We don't have a lower bound for 6 circles- Yes, we do. Just off of the top of my head, the lower bound's four times the number of the number of configurations for five circles: one where the sixth circle doesn't touch any of the five circle combinations, one where it encircles the five circle combinations, one where an arbitrarily-small circle is encircled by one (and only one) of the five circle combination circles, and one where an arbitrarily-small circle intersects one (and only one) of the five circle combination circles. The actual number would be much higher, of course, but that's a definite lower bound.
Date: 2022-04-09

Comments and reviews: 9


I submit the unhelpful upper bound for the arrangements of n circles as the number of arrangements of possible combinations of up to n elements: 2-(2-n)
This can be trivially narrowed further such as by removing all combinations that do not contain all n elements, but should provide a rough sense of scale for any attempt at brute forcing solutions for a given n.
This gives an upper bound for 6 of 2-(2-6)=2-64 -= 10-19 or roughly an exobyte of data.

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I have a question related to 4 circles configuration: does exist a configuration with 4 circles, not necessarily congruent, that replies the Venn Diagram, as it happens in case n = 3 at 2: 20? I mean, I would find a configuration with 4 circles, even different in size, in which all kinds of intersections appear. Currently, I'm not finding such a configuration. Could it be impossible?
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Actually, we do have a lower bound for 6 circles. It is twice that of the 5 case. This is due to the fact that we can either put a 6th circle next to all the cases for 5, and get 16, 000+ ways to draw 6 circles. You can also draw a 6th circle next to every possible way to draw 5. This will also give you 16, 000+ ways. So this must be at least twice the ways to draw 5.
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Surely the lower bound for 6 circles is at least 16, 951x3 no. So 50, 853. Since you could conceive of an arrangement of circles that is just the previous total arrangements plus on extra circle either seperate, crossing, or nested in some capacity.
Obviously the true answer is gonna be much higher than that but at least there's something

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You can overlap two shapes by making a pair of sides(one from each circle) go through each other. A circle has an infinite amount of sides. That means that you can overlap two circles with an infinite amount of ways to choose from. It doesn't matter how big or small or where the circles are located as long as the circles overlap.
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coming from a math fan who is not a mathematician, the graphic of the 4 circles with the 5th ellipse, it almost looks like a 3 dimensional representation of rings, and how the 5th -ring- would sit tangentially on top of a sphere. would this perspective shift, and view in 3 dimensions provide any special insight to this issue?
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Very interesting. Two questions I am left with:
Is this solved for triangles? I am genuinely unsure if it actually makes a difference, although I would imagine so.
Seeing as -touches- is not acknowledged as a separate state, does that mean that this is approached as a geometrical problem and not a topological one?

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It was said that we don't have an upper bound for the numbers of patterns above 5 circles, but wouldn't that be 2-2-n based on the table at the end? The table contains patterns that are impossible and also duplicates, so there's less patterns for the circles than in the table.
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This is really cool. I think the first step to figuring out how to take this further is to simplify what we know as far as possible. That chart of the configurations of four circles is painfully asymmetrical and makes random choices for the sake of visuals rather than uniform ones
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