
Linked List - Beau teaches JavaScript
video description
Date: 2022-03-14
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Comments and reviews: 10
Алексей
Thanks for your work. But how actually we save the next link to object. Is it reference or object? For example if I have 5 elements in a list and want get first element, I get in google console whole bunch of nesting object from the start to end. If javascript don't have a truly reference type like a C++ or Java maybe we should keep our data in array. What do you think about it? I actually don't know the method that get size in memory of object so I can't imagine how to test list. Also I think if you give es2015 syntax it would be more eye catching.
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Thanks for your work. But how actually we save the next link to object. Is it reference or object? For example if I have 5 elements in a list and want get first element, I get in google console whole bunch of nesting object from the start to end. If javascript don't have a truly reference type like a C++ or Java maybe we should keep our data in array. What do you think about it? I actually don't know the method that get size in memory of object so I can't imagine how to test list. Also I think if you give es2015 syntax it would be more eye catching.
reply
Nagaraju
Seems like you're returning the last element for -this.elementAt- function when we are passing the index greater than its size.
I guess this.elementAt function needs to be corrected with the below code:
this.elementAt = function (index) --
var currentNode = head;-
var count = 0;-
while (count < index) --
count++;-
if (currentNode.next) --
currentNode = currentNode.next;-
- else --
return -Element not found-;-
--
--
return currentNode.element;-
-;
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Seems like you're returning the last element for -this.elementAt- function when we are passing the index greater than its size.
I guess this.elementAt function needs to be corrected with the below code:
this.elementAt = function (index) --
var currentNode = head;-
var count = 0;-
while (count < index) --
count++;-
if (currentNode.next) --
currentNode = currentNode.next;-
- else --
return -Element not found-;-
--
--
return currentNode.element;-
-;
reply
cherub
Its just like Relay race, the head is the first runner who will pass the relay stick or (this.next) or NULL stick to the second runner , mind it that the second , third runner.....will be called (currentNode) the last runner is an exception which will be called the tail and it will be the last to hold the NULL stick , otherwise we want to add more runner .
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Its just like Relay race, the head is the first runner who will pass the relay stick or (this.next) or NULL stick to the second runner , mind it that the second , third runner.....will be called (currentNode) the last runner is an exception which will be called the tail and it will be the last to hold the NULL stick , otherwise we want to add more runner .
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Sheila
Thank you, I really like this. I like your codepen Linked List; I can go look at it, try to interpret what it does, and then come back and listen to your explanation. n.b. I realise your .add() method adds the new element to the end of the list, whereas you have a .addAt() method to insert a node at any other position of the list.
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Thank you, I really like this. I like your codepen Linked List; I can go look at it, try to interpret what it does, and then come back and listen to your explanation. n.b. I realise your .add() method adds the new element to the end of the list, whereas you have a .addAt() method to insert a node at any other position of the list.
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beqa
i don't feel like you need to check all element before add new one, what if you have last element object so when you add new element you just add lastPoint.next = node and then update lastPoint = node like so:
this.lastPoint.next = node
this.lastPoint = node;
and for first time lastPoint = this.head
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i don't feel like you need to check all element before add new one, what if you have last element object so when you add new element you just add lastPoint.next = node and then update lastPoint = node like so:
this.lastPoint.next = node
this.lastPoint = node;
and for first time lastPoint = this.head
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Marco
Great Video! There are some edge cases where this implementation would fail. Example: this.remove() length should only be decremented if the element is found. length-- should either be moved to both the if and else clause, or use some kind of flag set to true if it succeeds. Thanks
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Great Video! There are some edge cases where this implementation would fail. Example: this.remove() length should only be decremented if the element is found. length-- should either be moved to both the if and else clause, or use some kind of flag set to true if it succeeds. Thanks
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ctcrnitv
It says linked list has efficient insertions and deletions but I don't really get why. Isn't insertion/deletion normally O(n), and only if we're specifically inserting / deleting the head node it's O(1)? I might just be confused, also thanks for the great video.
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It says linked list has efficient insertions and deletions but I don't really get why. Isn't insertion/deletion normally O(n), and only if we're specifically inserting / deleting the head node it's O(1)? I might just be confused, also thanks for the great video.
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twice
this guy is good but it makes it hard for me to understand fully if this thing is already coded ... can u like try and walk us through by coding it not just explaining ... but I loved it though just need demonstration on the actually coding from scratch
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this guy is good but it makes it hard for me to understand fully if this thing is already coded ... can u like try and walk us through by coding it not just explaining ... but I loved it though just need demonstration on the actually coding from scratch
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Ricardo
I have a question. In the remove function, if we use as a parameter a non-existing element in the list, it will throw an error don't?? We should check not to exceed the length of the list in order to avoid that I think.
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I have a question. In the remove function, if we use as a parameter a non-existing element in the list, it will throw an error don't?? We should check not to exceed the length of the list in order to avoid that I think.
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endale
Thanks for making this video I really appreciate it! Just some feedback: You spoke really fast, I think it would've been better as a code along. All that code at the beginning can be pretty overwhelming
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Thanks for making this video I really appreciate it! Just some feedback: You spoke really fast, I think it would've been better as a code along. All that code at the beginning can be pretty overwhelming
reply
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