Unique Geometry Puzzle ( Maths Riddle ) From Hard Math Problems, Puzzles and Hardest Riddles
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Date: 2023-11-15
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Comments and reviews: 14
Vasudev
Just one thing. While you were adding 4 to a particular side, it would amount to adding 4 to only a length or breadth not both. E. g. if a smaller square had 12 cm side and another had 16 Cm side then adding 4 to 144 (area of 12 Cm square) would not make it equal ro area of 16 Cm square. Would the area of all squares add up to the area of the rectangle as mentioned in your solution?
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Just one thing. While you were adding 4 to a particular side, it would amount to adding 4 to only a length or breadth not both. E. g. if a smaller square had 12 cm side and another had 16 Cm side then adding 4 to 144 (area of 12 Cm square) would not make it equal ro area of 16 Cm square. Would the area of all squares add up to the area of the rectangle as mentioned in your solution?
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Curious_One
Here, one can just use one variable x.
Mark it as length of any one square next to square of 4.
Then, proceed marking all square lengths in terms of x.
Finally, get x by solving:
multiplying length and breadth of rect and equating to sum of all square areas.
Solve quadratic to get x.
Then, find overall area.
Though, this was awsome.
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Here, one can just use one variable x.
Mark it as length of any one square next to square of 4.
Then, proceed marking all square lengths in terms of x.
Finally, get x by solving:
multiplying length and breadth of rect and equating to sum of all square areas.
Solve quadratic to get x.
Then, find overall area.
Though, this was awsome.
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John
I used an approach similar to others, labeling the sides of square to the right of the 4 cm, as x.
I wound up in the top right square being x+44 at the top and the opposite side 3x-12. Setting them equal, you solve for x=28. Substituting back, the length across the top is 128 cm and the length down the side is 132 cm, the product being 16896 sq cm
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I used an approach similar to others, labeling the sides of square to the right of the 4 cm, as x.
I wound up in the top right square being x+44 at the top and the opposite side 3x-12. Setting them equal, you solve for x=28. Substituting back, the length across the top is 128 cm and the length down the side is 132 cm, the product being 16896 sq cm
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Komal
Since the puzzle involved mathematical calculation, I am happy that I was able to solve the puzzle. My approach was similar. Just I expressed the sides of all the squares using a single variable say 'x' and then I equated the two opposite lengths to get 'x'. Then we can easily get length and breadth of entire rectangle and then the area. -
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Since the puzzle involved mathematical calculation, I am happy that I was able to solve the puzzle. My approach was similar. Just I expressed the sides of all the squares using a single variable say 'x' and then I equated the two opposite lengths to get 'x'. Then we can easily get length and breadth of entire rectangle and then the area. -
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Gurmeet
I started with the sides of the given square as 1cm instead of 4cm, keeping calculations simple. And multiplied the sides of final square by 4 at the end. b=a+1, c=a+2, d=a=3, e=4, f=a+7, g=a+11, h=a+11-4 and so on using the same logic, I got my rectangle as 32x34. Mutiply both sides by 4 to get 128x132 = 16, 896 sq cm.
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I started with the sides of the given square as 1cm instead of 4cm, keeping calculations simple. And multiplied the sides of final square by 4 at the end. b=a+1, c=a+2, d=a=3, e=4, f=a+7, g=a+11, h=a+11-4 and so on using the same logic, I got my rectangle as 32x34. Mutiply both sides by 4 to get 128x132 = 16, 896 sq cm.
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Raj
Here. all squares doesn't have the same side. at the bottom. we have 3 square placed. whereas. if we see vertically. on the right hand side. only two squares are placed of different side length. this possible. since first we can make rectangle and draw squares inside of it. .
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Here. all squares doesn't have the same side. at the bottom. we have 3 square placed. whereas. if we see vertically. on the right hand side. only two squares are placed of different side length. this possible. since first we can make rectangle and draw squares inside of it. .
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Mridul
I did same. But I did one different. I already assume that E squared look double black squared so I assume it's length would be 16. Because if u look closely they are identical. Just double. But I think it's wrong thinking
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I did same. But I did one different. I already assume that E squared look double black squared so I assume it's length would be 16. Because if u look closely they are identical. Just double. But I think it's wrong thinking
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manu
Me after seeing the question
- it's beyond my capability. Let's see the answer-
Me after seeing the answer
- I could have done that
Moral: never give up without trying-
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Me after seeing the question
- it's beyond my capability. Let's see the answer-
Me after seeing the answer
- I could have done that
Moral: never give up without trying-
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Jan
and i was always saying, that some a+b-d-c + one cow and whatever, is absolutely useless in my life. And. i was RIGHT!
but. Great video to see it have some purpose: )
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and i was always saying, that some a+b-d-c + one cow and whatever, is absolutely useless in my life. And. i was RIGHT!
but. Great video to see it have some purpose: )
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Komal
Out of ur all the puzzle, I was able to able to solve only this puzzle within few minutes and was really happy when I saw that our approach was similar. .--
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Out of ur all the puzzle, I was able to able to solve only this puzzle within few minutes and was really happy when I saw that our approach was similar. .--
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Sahil
Logically Yours = Best puzzles
Only few of puzzles i could solve and geometrical ones are my strength
I solved this puzzle same way.
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Logically Yours = Best puzzles
Only few of puzzles i could solve and geometrical ones are my strength
I solved this puzzle same way.
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Vasudev
You haven-t replied to my below comment. So should I assume that my observation is correct and the answer given in the video is wrong?
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You haven-t replied to my below comment. So should I assume that my observation is correct and the answer given in the video is wrong?
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SHAILESH
I took left lower corner as x then x-4, x+4, x-8, 16, x+20, 2x-12, x+36 then equate top and bottom side to find x which is 36.
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I took left lower corner as x then x-4, x+4, x-8, 16, x+20, 2x-12, x+36 then equate top and bottom side to find x which is 36.
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education
At 2: 51 instead of calculating h if we had calculated a the problem would have had solved there itself.
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At 2: 51 instead of calculating h if we had calculated a the problem would have had solved there itself.
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