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zakruti.com » Knowledge, science, education » Numberphile
3 as the sum of the 3 cubes - Numberphile

3 as the sum of the 3 cubes - Numberphile

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3 as the sum of the 3 cubes louis: Cracking the problem with 33 would make a great STEM day talk at schools. I think that the paper could even be a short seminar at sixth forms, even secondary depending on the depth covered. The source, accepting that the optimizations, assembler are do not lend themselves to readability would still be a valuable thing to see. You can appreciate that which you can see better than that which you are told. Please release it! -Number theory a short course beginning with 42. -
Date: 2022-04-09

Comments and reviews: 9


Wait, 41 - 3 Ends With 921! (Value Is 68, 921)
(32 - 3) - (6 - 3) + (3 - 3) Is Another Way To Make A Number End With 579! (32, 768 - 216 + 27 = 32, 579)
Why Not Look On The 1st One Thousand Cube Numbers, Then Search For Possibilities Of What Digits Would Integers Greater Than 100 Quadrillion (For All 3 Cubes) Would Make 114, 390, 579, 627, 633, 732, 921, Also 975!

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Brady asks the most amazing and lucid questions. For example when he asked if there was a smaller solution they might have brushed past. Its like he read my mind and said what i was thinking without me being aware of what i was even thinking myself. Thank you Brady. And keep in mind you are a very big part of the reason me, and many others, love maths.
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How does it work?
Any number with fraction power eg
2-(2/5) will simple calculator solve this?
Try this
1. Type 2 press 12 times root
2. Then press -(minus) 1
3. Then multiply 2
4. Then divide 5
5. Then add 1
6. Then press =
7. Then x= x=. 12 time
Boom you got the answer anymore tell how it works.

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I wish they would speak a bit more about the 'why'.
We do hard things so that we discover other useful things in the process.
When we put people on Mars we will discover other useful things in the process.
This is and always will be the way of doing things that are hard.

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Are these kind of combinations also done for 4 terms? I mean for the squares (exponent 2, there are 3 terms. So, for exponent 3, then just increase the number of the terms, too
(I have absolutely no idea what I'm talking about)
edit: ok. now, I arrived at 5: 41 in the video: D

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Dude, you got 24 = (1139873642443924761440)-3 + (-1139873642227126987018)-3 + (-945430986906654064)-3
By just dividing the numbers with 2 (since 2-3=8 and 8-3=24) you could have got 3 = (569936821221962380720)-3 + (-569936821113563493509)-3 + (-472715493453327032)-3

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Thank you very much sir for updating this information. Sir Now I want to know that how researchers had found this number. I mean that Is there any Parametric solution to find or arise any elliptic curves to solve this types of problems. Sir kindly tell me please.
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-So, why don't you just clean your Petri dishes? -
-I expect to invent Penicilin any day now-
- a discussion that definitely didn't happen before the invention of Penicilin
(a comment on -why are you doing this instead of something useful-)

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-So what do you do for a living? -
-I try figuring out unknown solutions for the sum of three cubes. -
-But. but why? -
-Because we don't know them yet. -
-Yeah, but why do you want to know them! -
-Because. we don't know them yet. -

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