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zakruti.com » Knowledge, science, education » Logically Yours
The Crazy Gangster Puzzle Russian Roulette Puzzle

The Crazy Gangster Puzzle Russian Roulette Puzzle

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Rating: 4.0; Vote: 1
The Crazy Gangster Puzzle -- Russian Roulette Puzzle Mycroft616: Mathematical answer: Fire right away. The first shot was one of four empty chambers. Of those four chambers, three have a subsequent chamber that's empty. The fourth's is loaded. Therefore, there's a 75% chance of not getting a bullet on the next shot if we take the next chamber. However, spinning the cylinder resets the odds, returning us to a 66% chance of survival.
Physical answer: Depends on how he spins the cylinder, whether he interferes with the spin or doesn't set the cylinder until it stops spinning by itself, the weight of the bullets, and the design of the revolver. By loading only two chambers and not setting the bullets in opposite chambers, the cylinder's center of gravity is no longer aligned with the cylinder's axis of rotation. If he points the revolver downwards while the cylinder spins, this offset causes little change. If he holds the revolver upright so the barrel is parallel to the ground, the offset will cause a higher chance of the bullets settling in the lower chambers. The specific probability of this is dictated by the weight of the bullets used; heavier bullets mean higher probability the bullets will not reach the top chambers. Furthermore, the solution is also dependent on whether the revolver uses the bullet loaded in the highest chamber or the lowest chamber. However, all of this is negated if he interferes with the cylinder. Without these specifics, there's not enough information to discern which is more logical.

Date: 2023-11-15

Comments and reviews: 29


Hm, my theory before checking comments or watching the ending but a revolver might not really work like that, I mean how flawlessly would a revolver spin so the -heavy- side is on the bottom? But if that's the case then a new spin, if also allowed to finish the spin -naturally- would mean the two bullets would be at the bottom and recycle to one clear chamber in the worst case (as it cycles once when cocking the gun, thanks Alec Baldwin.
If it wouldn't be spun and directly fired and my spin+gravity theory is correct the gun would likely fire if it isn't spun anew, so the chances would overall be better for option 1.
Ofc that only works if the theory is correct but also might depend. hey technically either option is fine if it's a single action revolver as if he just pulls the trigger (hence without cocking the gun) nothing would happen hence it's safe in both scenarios xD (also thanks Alec Baldwin for indirectly teaching me this lesson xD )
Edit: Okay guess gravity isn't even an option, I wonder if that would be the case though, or what the parameters would be, also again in a single action revolver the survival odds are 100%, unless the gun is malfunctioning of course.

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Nice problem, two questions, though: shouldn't we take into account that statistically speaking with many shots with bullets still in chambers the chance of firing a bullet gets higher? Because statistically speaking you should fire two bullets per six shots, you cannot expect magically not to fire a single bullet for 100 shots and still give it a chance of only 1/3 on the next shot. So, even on the second shot the odds should get slightly worse with none bullet fired (as well as better with one fired, if not to your head, of course.
Interesting question: if the cylinder had to be spinned after each shot and the first shot would be lucky for you as in the video, would you try your chance with the 2nd shot, or would you ask for one shot to a blank and go with the 3rd one?

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No. 2 because if he was not able to kill you despite putting his gun to the head, it means a few things.
1. He has a toy gun.
2. He can't shoot. And if he can't shoot despite LITERALLY putting the gun on your head, then just run a few distances because he will 100% miss.
Another solution is not to answer the question itself. Just beat the shit outta the guy. Take him by surprise.
Think outside the box my ass.

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Your solution is not logical, because you claim the spent round was replaced on the second shot, (replaced the spent bullet with a live round.
You don-t mention this in the rules. It clearly states he pulls the trigger a second time, NOT that he replaces the round and pulls the trigger a second time. This omission changes everything.

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Nice riddel. Nice graphic explenation, as always.
But! Ok. I choose the first option of the 75% to survive.
The gangster pull the trigger, BOOM! Im dead.
Math didn't help me this time. Ha?
Ty Ammar for nice video, I-m in heaven now. Everybody here are waiting to the next video (-:

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sorry. but i think the chance of survival was calculated like this:
if one of the empty chamber is triggered, it leaves 60% (3 empty 2 loaded) since the first shot has been taken
and if you respin, chance are 66% (4 empty 2 loaded)
i think is simple as that.

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Wouldnt it give you higher chances if you respin the barrel since bullets are loaded besides one another resulting to the center of gravity of barel to shift and chances are bullets will stablize the rotation when bullets are at the bottom part of the barrel
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Pull the trigger right away is not the correct answer, since you can never reach the 'A' position because, there was a bullet insife it, but you managed to survive from it, so it should be 66% only.
2/3 as A is impossible
Lol, I comment it on 2021: V

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Spin again since after surviving, you now have 5 chambers and 2 bullets thus a 40% chance of being hit since one of the six chambers is no longer in play, but prior to that your chance WAS 1/3 (33 1/3%) as there were 2 bullets out of 6 chambers all in play.
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I think u have wrong logic in this puzzle. Without spin. 2 loaded 3 blank chance of survival is 3/5=0. 6
With spin. 2 loaded 4 blank chances of survival is. 4/6=0. 67
So after spin is better for him to maximize the chance to survival.

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Yeah Ammar
Out side the box
While spin the bullet camber due to gravitational force the bullets occupy the bottom of the area of the chambers, even after n no of time we will have got a chance to survive
Pls review my comment

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You can also look at this from the point of where the chamber is, in no spin only one chamber in 6 the one before the loaded bullets results in death ie 1/6 chance in the spin scenario there is 2/6 chance
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What if a gangster put bullets randomly, for instance on A and C? Your chances will dramatically reduced to only 50% (D and E are safe, B and F not, so your choice should be depend on the bullets position
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Puzzles only work when you are dumbed down and not be able to think outside the box. Why the heck would you answer the question, when you could just take him by surprise as he speaks his ass?
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according to an article on this question ' missing from the interview question is the assumption candidate know that a revolver cylinder advances one position after each pull of the trigger'
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Actually re-spinning the wheels doesn't reset your chances, meaning the probability to have an empty chamber second time is P(first_time)-P(seconds_time)=(4/6)-2 = 44%. Do never ask to spin.
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You're wrong! If there will be a spin for the 2nd shot, with only 1 bullet left, you would have a 5/6 chance to survive, which is the best. By the way, you pronounce it all wrong as well.
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Bro how can you say in 1st option, there are 4 safe chances out of 6. He has already fired the 1st shot and then asking for spinning. So technically the equation becomes 5/6 and not 4/6
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In questions from previous comment, if safe strategy changes to spin, then we can safely say that biological phenomenon of -There is safety in numbers- gets mathematically proven.
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Well the correct answer will be respinning, as after 1 shot is fired, the remaining bullet is 1 out of 6 boxes. So the probability to be safe will be 5/6, which is greater than 75%
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I think in case of respin the probability of survivng is 60%. Since 1 bullet is shot which was empty, now there 3 empty and 2 bullets. So chance of survivng is 3/5=60%. Thank you.
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Bro! If he Spins the cylinder, Then Due to weight of the bullet the chambers with bullet will be in the bottom!
and chances are increased much more! Think scientifically!

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Its wrong, in first case he's considering the empty slots(3/4, where as in 2nd case he's considering all, the empty one as well as the filled one so the prob. decreases.
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Solution was pretty simple. Even when I thought of it, I actually stayed paused for a while trying to think if I was missing something because it seemed too easy.
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Different numbers, think out of the box. No spin, second shot is a 2/5 chance of getting shot = 40%. Spin = 2/6 chance of getting shot = 33. 3%. Spin that chamber!
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After the first bullet is shot, only one bullet is remaining, so the chances of surviving in the second scenario are rather 5/6 = 83% which is the best option
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2: 28, make sense given that the bullets were adjacent (next to each other, if bullets were not adjacent, then spin again would be best chance of surviving.
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After he spins it, the chambers with bullet would be towards the lower side due to the gravitational acceleration. Hence, I'd ask him to spin it again.
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First option is 100% safe
When the gangster re spin both bullet go down because of its weight
So when he fire the gun the shot will be in B or C

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