Can you survive the creation of the universe by solving this riddle? - James Tanton
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Date: 2022-02-24
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Comments and reviews: 10
Averin
I took 1 minute and 37 seconds.
My strategy was similar to the one at the end of the video. It doesn't really matter how many anti-matter particles are to your left, and thus, you should maximize the number of anti-matter particles in a sequence to your left, and maximize the number of matter particles to your right. That removes a ton of the starting positions already, just compare the ones left and make sure that the number of matter particles minus anti-matter particles equal to 0. Thankfully, this is one puzzle that I am actually able to solve.
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I took 1 minute and 37 seconds.
My strategy was similar to the one at the end of the video. It doesn't really matter how many anti-matter particles are to your left, and thus, you should maximize the number of anti-matter particles in a sequence to your left, and maximize the number of matter particles to your right. That removes a ton of the starting positions already, just compare the ones left and make sure that the number of matter particles minus anti-matter particles equal to 0. Thankfully, this is one puzzle that I am actually able to solve.
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Jam
Took me 1 minute and 2 seconds.
I now wonder if it's correct. the strategy is to just. find the longest row of antimatter, then keep that point in mind.
Then you want to see the direct right of it (which will first always be a matter, start counting each thing you see, for every matter, add 1, for every anti matter, minus 1. If it ever goes negative, restart the counter to the right of the antimatter that causes it to be negative, if you finally end up with 0 after a full cycle, there's your spot.
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Took me 1 minute and 2 seconds.
I now wonder if it's correct. the strategy is to just. find the longest row of antimatter, then keep that point in mind.
Then you want to see the direct right of it (which will first always be a matter, start counting each thing you see, for every matter, add 1, for every anti matter, minus 1. If it ever goes negative, restart the counter to the right of the antimatter that causes it to be negative, if you finally end up with 0 after a full cycle, there's your spot.
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Elio
I believe there is a simpler way, yet similar. Let S be the sum of any consecutive matter particles, AS the sum of consecutive antimatter particles on their right and finally D(i)=S(i)-AS(i. All we need now is to find the minimum among D(i) and place the matter on the left of the corresponding matter consecutive particles. This allows completing the task with a computational cost of N instead of N N where N is the total number of particles.
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I believe there is a simpler way, yet similar. Let S be the sum of any consecutive matter particles, AS the sum of consecutive antimatter particles on their right and finally D(i)=S(i)-AS(i. All we need now is to find the minimum among D(i) and place the matter on the left of the corresponding matter consecutive particles. This allows completing the task with a computational cost of N instead of N N where N is the total number of particles.
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Ala
Ok, so I came up with a different solution. If you get annihilated when you get an antimatter particle to your right, wouldn't you just need to choose the longest uninterrupted sequence of matter particles and place yourself to the left of it? Yes, as the video shows, there are more safe spots than just this one, but this one is definetely safe and you don't have to count the pairs so it's quicker. Or am I missing something?
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Ok, so I came up with a different solution. If you get annihilated when you get an antimatter particle to your right, wouldn't you just need to choose the longest uninterrupted sequence of matter particles and place yourself to the left of it? Yes, as the video shows, there are more safe spots than just this one, but this one is definetely safe and you don't have to count the pairs so it's quicker. Or am I missing something?
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Tri
I recognized the strategy within 30 seconds! I realized that the condition was standing to the left of another antiparticle, and not to the right led to anihilation, so I reasoned that finding the longest string of gluons and standing to the leftmost position will leave only you standing. Typically though, I can't figure these questions out, so that made me very happy!
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I recognized the strategy within 30 seconds! I realized that the condition was standing to the left of another antiparticle, and not to the right led to anihilation, so I reasoned that finding the longest string of gluons and standing to the leftmost position will leave only you standing. Typically though, I can't figure these questions out, so that made me very happy!
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EricStelzman
Our whole universe was in a hot, dense state.
Then nearly 14 billion years ago, expansion started
Wait.
The Earth began to cool, the autotrophs began to drool,
Neanderthals developed tools, we built a wall
(We built the pyramids.
Math, science, history,
Unravelling the mystery
That all started with the Big. BANG!
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Our whole universe was in a hot, dense state.
Then nearly 14 billion years ago, expansion started
Wait.
The Earth began to cool, the autotrophs began to drool,
Neanderthals developed tools, we built a wall
(We built the pyramids.
Math, science, history,
Unravelling the mystery
That all started with the Big. BANG!
reply
BarharborBasher
Darwinism 101
9 months ago
your parents had a Big Bang
Triggering a coronal mass ejaculation
Hence the primordial ooze
Seed forms a tale and is aquatic
Grows limbs resembling a monkey
leaves the waters for land.
Everything can t come from nothing
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Darwinism 101
9 months ago
your parents had a Big Bang
Triggering a coronal mass ejaculation
Hence the primordial ooze
Seed forms a tale and is aquatic
Grows limbs resembling a monkey
leaves the waters for land.
Everything can t come from nothing
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Alone
The strategy that popped up in my mind is you want to be at the farthest left on the group of particles where that group outnumbers the group of anti-particle to its right.
It worked but I didn't realize the second one had multiple solutions.
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The strategy that popped up in my mind is you want to be at the farthest left on the group of particles where that group outnumbers the group of anti-particle to its right.
It worked but I didn't realize the second one had multiple solutions.
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Shiny
I don't know how friendly the other particles can be if their idea of fun is Mutually Assured Destruction.
Personally I would accelerate so much into the other direction that I become the first photon.
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I don't know how friendly the other particles can be if their idea of fun is Mutually Assured Destruction.
Personally I would accelerate so much into the other direction that I become the first photon.
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Van
Well. That was easy. Took about a minute. Less than a minute for the coding program, possibly. Despite the fact I'm thinking more about the war in Ukraine, rather than abstract riddles.
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Well. That was easy. Took about a minute. Less than a minute for the coding program, possibly. Despite the fact I'm thinking more about the war in Ukraine, rather than abstract riddles.
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